§ Задание 460
\[\boxed{\text{5.460.}}\]
\[\frac{3}{20} \cdot 4 = \frac{12}{20} = \frac{3}{5}\ (дм) -\]
\[периметр\ квадрата.\]
\[Ответ:\ \frac{3}{5}\ дм.\]
\[\boxed{\text{5.460.}}\]
\[\frac{3}{20} \cdot 4 = \frac{12}{20} = \frac{3}{5}\ (дм) -\]
\[периметр\ квадрата.\]
\[Ответ:\ \frac{3}{5}\ дм.\]