§ Задание 562
\[1)\ P(A) = \frac{3}{3 + 4 + 5} = \frac{3}{12} = \frac{1}{4};\]
\[2)\ P(A) = \frac{3 + 4}{3 + 4 + 5} = \frac{7}{12}.\]
\[1)\ P(A) = \frac{3}{3 + 4 + 5} = \frac{3}{12} = \frac{1}{4};\]
\[2)\ P(A) = \frac{3 + 4}{3 + 4 + 5} = \frac{7}{12}.\]