$$\frac{12\frac{4}{5} \cdot 3\frac{3}{4} - 4\frac{4}{11} \cdot 4\frac{1}{8}}{11\frac{2}{3} : \frac{7}{18}} = \frac{\frac{64}{5} \cdot \frac{15}{4} - \frac{48}{11} \cdot \frac{33}{8}}{\frac{35}{3} : \frac{7}{18}} = \frac{\frac{64 \cdot 15}{5 \cdot 4} - \frac{48 \cdot 33}{11 \cdot 8}}{\frac{35 \cdot 18}{3 \cdot 7}} = \frac{\frac{16 \cdot 3}{1} - \frac{6 \cdot 3}{1}}{\frac{5 \cdot 6}{1}} = \frac{48 - 18}{30} = \frac{30}{30} = 1$$
Ответ: 1