Вопрос:

Заполните пропуски: а) 2 2/5 + 7 3/10 = □ + □/10 + 3/10 = □ 7/10; б) 6 7/8 + 3 5/12 = □ + □/24 + □/24 = □ + □/24 = □ 31/24 = □ □/24; в) 8 1/9 + 2 3/5 = 10 + □/45 + □/45 = 10 □/45; г) 9 2/7 + 5 = □ 2/7; д) 5 + 2 11/19 = □ □/19; е) 1 − 3/7 = □/7 − 3/7 = □/□.

Ответ:

а) \(2\frac{2}{5}+7\frac{3}{10}=9+\frac{4}{10}+\frac{3}{10}=9\frac{7}{10}\).

б) \(6\frac{7}{8}+3\frac{5}{12}=9+\frac{21}{24}+\frac{10}{24}=9+\frac{31}{24}=10\frac{7}{24}=10\frac{31}{24}\).

в) \(8\frac{1}{9}+2\frac{3}{5}=10+\frac{5}{45}+\frac{27}{45}=10\frac{32}{45}\).

г) \(9\frac{2}{7}+5=14\frac{2}{7}\).

д) \(5+2\frac{11}{19}=7\frac{11}{19}\).

е) \(1-\frac{3}{7}=\frac{7}{7}-\frac{3}{7}=\frac{4}{7}\).