Вопрос:

Задание Б. Найдите значение выражения при данных значениях переменных a и b:

Ответ:

Решение:

Дано: \( a = 1, b = -1 \) или \( a = 2, b = -3 \) или \( a = -1, b = -1 \).

Выражениеa = 1, b = -1a = 2, b = -3a = -1, b = -1
1) 2a + b\(2(1) + (-1) = 2 - 1 = 1\)\(2(2) + (-3) = 4 - 3 = 1\)\(2(-1) + (-1) = -2 - 1 = -3\)
2) 2(a + b)\(2(1 + (-1)) = 2(0) = 0\)\(2(2 + (-3)) = 2(-1) = -2\)\(2(-1 + (-1)) = 2(-2) = -4\)
3) 2a + b²\(2(1) + (-1)² = 2 + 1 = 3\)\(2(2) + (-3)² = 4 + 9 = 13\)\(2(-1) + (-1)² = -2 + 1 = -1\)
4) 2(a + b²)\(2(1 + (-1)²) = 2(1 + 1) = 2(2) = 4\)\(2(2 + (-3)²) = 2(2 + 9) = 2(11) = 22\)\(2(-1 + (-1)²) = 2(-1 + 1) = 2(0) = 0\)
5) 2(a + b)²\(2(1 + (-1))² = 2(0)² = 0\)\(2(2 + (-3))² = 2(-1)² = 2(1) = 2\)\(2(-1 + (-1))² = 2(-2)² = 2(4) = 8\)
6) 2a² + b\(2(1)² + (-1) = 2(1) - 1 = 2 - 1 = 1\)\(2(2)² + (-3) = 2(4) - 3 = 8 - 3 = 5\)\(2(-1)² + (-1) = 2(1) - 1 = 2 - 1 = 1\)
7) 2(a² + b)\(2(1² + (-1)) = 2(1 - 1) = 2(0) = 0\)\(2(2² + (-3)) = 2(4 - 3) = 2(1) = 2\)\(2((-1)² + (-1)) = 2(1 - 1) = 2(0) = 0\)
8) 2a² + b²\(2(1)² + (-1)² = 2(1) + 1 = 2 + 1 = 3\)\(2(2)² + (-3)² = 2(4) + 9 = 8 + 9 = 17\)\(2(-1)² + (-1)² = 2(1) + 1 = 2 + 1 = 3\)
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