Ответ:
Чтобы перевести смешанную дробь в неправильную, умножаем целую часть на знаменатель, прибавляем числитель и записываем результат над прежним знаменателем.
- \(1\frac{9}{27}=\frac{1\cdot27+9}{27}=\frac{36}{27}=\frac{4}{3}\).
- \(1\frac{22}{24}=\frac{1\cdot24+22}{24}=\frac{46}{24}=\frac{23}{12}\).
- \(6\frac{1}{5}=\frac{6\cdot5+1}{5}=\frac{31}{5}\).
- \(1\frac{22}{25}=\frac{1\cdot25+22}{25}=\frac{47}{25}\).
- \(1\frac{13}{30}=\frac{1\cdot30+13}{30}=\frac{43}{30}\).
- \(10\frac{1}{6}=\frac{10\cdot6+1}{6}=\frac{61}{6}\).
- \(9\frac{5}{10}=\frac{9\cdot10+5}{10}=\frac{95}{10}=\frac{19}{2}\).
- \(4\frac{1}{2}=\frac{4\cdot2+1}{2}=\frac{9}{2}\).
- \(5\frac{9}{12}=\frac{5\cdot12+9}{12}=\frac{69}{12}=\frac{23}{4}\).
- \(8\frac{2}{10}=\frac{8\cdot10+2}{10}=\frac{82}{10}=\frac{41}{5}\).
- \(1\frac{21}{30}=\frac{1\cdot30+21}{30}=\frac{51}{30}=\frac{17}{10}\).
- \(3\frac{17}{20}=\frac{3\cdot20+17}{20}=\frac{77}{20}\).
- \(3\frac{3}{10}=\frac{3\cdot10+3}{10}=\frac{33}{10}\).
- \(2\frac{6}{24}=\frac{2\cdot24+6}{24}=\frac{54}{24}=\frac{9}{4}\).
- \(9\frac{3}{5}=\frac{9\cdot5+3}{5}=\frac{48}{5}\).
- \(10\frac{3}{4}=\frac{10\cdot4+3}{4}=\frac{43}{4}\).
- \(5\frac{3}{8}=\frac{5\cdot8+3}{8}=\frac{43}{8}\).
- \(3\frac{6}{15}=\frac{3\cdot15+6}{15}=\frac{51}{15}=\frac{17}{5}\).
- \(3\frac{9}{25}=\frac{3\cdot25+9}{25}=\frac{84}{25}\).
- \(2\frac{7}{30}=\frac{2\cdot30+7}{30}=\frac{67}{30}\).
Ответ: 1) \(\frac{4}{3}\); 2) \(\frac{23}{12}\); 3) \(\frac{31}{5}\); 4) \(\frac{47}{25}\); 5) \(\frac{43}{30}\); 6) \(\frac{61}{6}\); 7) \(\frac{19}{2}\); 8) \(\frac{9}{2}\); 9) \(\frac{23}{4}\); 10) \(\frac{41}{5}\); 11) \(\frac{17}{10}\); 12) \(\frac{77}{20}\); 13) \(\frac{33}{10}\); 14) \(\frac{9}{4}\); 15) \(\frac{48}{5}\); 16) \(\frac{43}{4}\); 17) \(\frac{43}{8}\); 18) \(\frac{17}{5}\); 19) \(\frac{84}{25}\); 20) \(\frac{67}{30}\).
