Задание 2. Найди значение выражения (по действиям): а) \(-\frac{3}{4}:\frac{5}{6}-2\frac{1}{2}\cdot\frac{2}{5}+1:1\frac{1}{9}\); б) \(2\frac{3}{4}\cdot(-\frac{2}{5}+1\frac{1}{2})-(-\frac{3}{4}-\frac{5}{6}):3\frac{1}{6}\); в) \((-\frac{2}{15}-1\frac{7}{12})\cdot\frac{30}{103}+2:2\frac{1}{4}-\frac{9}{32}\); г) \((-3\frac{1}{2}:4\frac{2}{3}-4\frac{2}{3}:3\frac{1}{2})\cdot(-4\frac{4}{5})\). Дополнительно вычисли: 1) \((0{,}1955+0{,}187):0{,}085\); 2) \(15{,}76267:(100{,}6+42{,}697)\); 3) \((86{,}9+667{,}6):(37{,}1+13{,}2)\); 4) \((9{,}09-9{,}0252)\cdot(25{,}007-12{,}507)\).

а) \(-\frac{3}{4}:\frac{5}{6}-2\frac{1}{2}\cdot\frac{2}{5}+1:1\frac{1}{9}=-\frac{9}{10}-1+\frac{9}{10}=-1\).

б) \(2\frac{3}{4}\cdot(-\frac{2}{5}+1\frac{1}{2})-(-\frac{3}{4}-\frac{5}{6}):3\frac{1}{6}=\frac{11}{4}\cdot\frac{11}{10}-(-\frac{19}{12}):\frac{19}{6}=\frac{121}{40}+\frac{1}{2}=\frac{141}{40}=3\frac{21}{40}\).

в) \((-\frac{2}{15}-1\frac{7}{12})\cdot\frac{30}{103}+2:2\frac{1}{4}-\frac{9}{32}=(-\frac{2}{15}-\frac{19}{12})\cdot\frac{30}{103}+\frac{8}{9}-\frac{9}{32}= -\frac{103}{60}\cdot\frac{30}{103}+\frac{8}{9}-\frac{9}{32}= -\frac{1}{2}+\frac{8}{9}-\frac{9}{32}=\frac{13}{288}\).

г) \((-3\frac{1}{2}:4\frac{2}{3}-4\frac{2}{3}:3\frac{1}{2})\cdot(-4\frac{4}{5})=(-\frac{7}{2}:\frac{14}{3}-\frac{14}{3}:\frac{7}{2})\cdot(-\frac{24}{5})=(-\frac{3}{4}-\frac{4}{3})\cdot(-\frac{24}{5})=\frac{25}{12}\cdot\frac{24}{5}=10\).

1) \((0{,}1955+0{,}187):0{,}085=0{,}3825:0{,}085=4{,}5\).

2) \(15{,}76267:(100{,}6+42{,}697)=15{,}76267:143{,}297=0{,}11\).

3) \((86{,}9+667{,}6):(37{,}1+13{,}2)=754{,}5:50{,}3=15\).

4) \((9{,}09-9{,}0252)\cdot(25{,}007-12{,}507)=0{,}0648\cdot12{,}5=0{,}81\).