Задание 48. Зная, что ДАВС ~ AMKL, заполните таблицу. Сходственные стороны AB MK PABC PMKL SABC SMKL 1) 12 30 k= 12 2 30 5 2 5 ( 2 5 )2 = 4 25

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Вопрос:

Задание 48. Зная, что ДАВС ~ AMKL, заполните таблицу. Сходственные стороны AB MK PABC PMKL SABC SMKL 1) 12 30 k= 12 2 30 5 2 5 ( 2 5 )2 = 4 25

Ответ:

ФИО:Телефон:Емаил:Полное описание сути нарушения прав (почему распространение данной информации запрещено Правообладателем):

Accepted Answer

1) $$k = \frac{AB}{MK} = \frac{12}{30} = \frac{2}{5}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{2}{5}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{2}{5})^2 = \frac{4}{25}$$

2) $$k = \frac{AB}{MK} = \frac{5}{3}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{5}{3}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{5}{3})^2 = \frac{25}{9}$$

3) $$k = \frac{AB}{MK} = \frac{10}{7}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{10}{7}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{10}{7})^2 = \frac{100}{49}$$

4) $$k = \frac{AB}{MK} = \frac{3}{2}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{3}{2}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{3}{2})^2 = \frac{9}{4}$$

5) $$k = \frac{AB}{MK} = \frac{9}{12} = \frac{3}{4}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{3}{4}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{3}{4})^2 = \frac{9}{16}$$

6) $$k = \frac{AB}{MK} = \frac{5}{30} = \frac{1}{6}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{1}{6}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{1}{6})^2 = \frac{1}{36}$$

7) $$k = \frac{AB}{MK} = \frac{16}{10} = \frac{8}{5}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{8}{5}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{8}{5})^2 = \frac{64}{25}$$

8) $$k = \frac{AB}{MK} = \frac{\sqrt{5}}{2}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{\sqrt{5}}{2}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{\sqrt{5}}{2})^2 = \frac{5}{4}$$

9) $$k = \frac{AB}{MK} = \frac{11}{\sqrt{7}}$$, $$\frac{P_{ABC}}{P_{MKL}} = \frac{11}{\sqrt{7}}$$, $$\frac{S_{ABC}}{S_{MKL}} = (\frac{11}{\sqrt{7}})^2 = \frac{121}{7}$$

10) $$k = \frac{AB}{MK} = \frac{6}{\sqrt{3}} = 2\sqrt{3}$$, $$\frac{P_{ABC}}{P_{MKL}} = 2\sqrt{3}$$, $$\frac{S_{ABC}}{S_{MKL}} = (2\sqrt{3})^2 = 12$$

	AB	MK	$$k=\frac{AB}{MK}$$	$$\frac{P_{ABC}}{P_{MKL}}$$/th>	$$\frac{S_{ABC}}{S_{MKL}}$$
1)	12	30	$$\frac{12}{30}=\frac{2}{5}$$	$$\frac{2}{5}$$	$$\frac{4}{25}$$
2)	5	3	$$\frac{5}{3}$$	$$\frac{5}{3}$$	$$\frac{25}{9}$$
3)	10	7	$$\frac{10}{7}$$	$$\frac{10}{7}$$	$$\frac{100}{49}$$
4)	3	2	$$\frac{3}{2}$$	$$\frac{3}{2}$$	$$\frac{9}{4}$$
5)	9	12	$$\frac{9}{12}=\frac{3}{4}$$	$$\frac{3}{4}$$	$$\frac{9}{16}$$
6)	5	30	$$\frac{5}{30}=\frac{1}{6}$$	$$\frac{1}{6}$$	$$\frac{1}{36}$$
7)	16	10	$$\frac{16}{10}=\frac{8}{5}$$	$$\frac{8}{5}$$	$$\frac{64}{25}$$
8)	$$\sqrt{5}$$	2	$$\frac{\sqrt{5}}{2}$$	$$\frac{\sqrt{5}}{2}$$	$$\frac{5}{4}$$
9)	11	$$\sqrt{7}$$	$$\frac{11}{\sqrt{7}}$$	$$\frac{11}{\sqrt{7}}$$	$$\frac{121}{7}$$
10)	6	$$\sqrt{3}$$	$$\frac{6}{\sqrt{3}}$$	$$\frac{6}{\sqrt{3}}$$	$$\frac{36}{3}=12$$

Ответ: смотри таблицу выше