Вопрос:

Задание 5. Выполни действия со смешанными числами. 1.$$2\frac{5}{13}+5\frac{8}{13}$$ 2.$$9\frac{15}{21}-3\frac{10}{21}$$ 3.$$10\frac{16}{34}-1\frac{14}{34}$$ 4.$$6\frac{7}{15}+9\frac{13}{15}$$ 5.$$15\frac{1}{10}-6\frac{4}{10}$$ 6.$$3\frac{6}{17}-2\frac{7}{17}$$ 7.$$23\frac{6}{19}-15\frac{16}{19}$$ 8.$$17\frac{6}{17}-15\frac{9}{17}$$ 9.$$5\frac{9}{23}-4\frac{15}{23}$$ 10.$$10\frac{1}{9}-3\frac{5}{9}$$ 11.$$12\frac{8}{10}-10\frac{9}{10}$$ 12.$$5\frac{2}{7}-4\frac{5}{7}$$ 13.$$2\frac{3}{5}+3\frac{4}{5}$$ 14.$$11\frac{6}{7}+13\frac{5}{7}$$ 15.$$8\frac{9}{16}-7\frac{5}{16}$$ 16.$$10\frac{5}{9}-4\frac{5}{9}$$

Смотреть решения всех заданий с листа

Ответ:

Решим примеры:

  1. $$2\frac{5}{13}+5\frac{8}{13}=(2+5)+(\frac{5}{13}+\frac{8}{13})=7+\frac{13}{13}=7+1=8$$
  2. $$9\frac{15}{21}-3\frac{10}{21}=(9-3)+(\frac{15}{21}-\frac{10}{21})=6+\frac{5}{21}=6\frac{5}{21}$$
  3. $$10\frac{16}{34}-1\frac{14}{34}=(10-1)+(\frac{16}{34}-\frac{14}{34})=9+\frac{2}{34}=9\frac{1}{17}$$
  4. $$6\frac{7}{15}+9\frac{13}{15}=(6+9)+(\frac{7}{15}+\frac{13}{15})=15+\frac{20}{15}=15+1\frac{5}{15}=16\frac{1}{3}$$
  5. $$15\frac{1}{10}-6\frac{4}{10}=(15-6)+(\frac{1}{10}-\frac{4}{10})=9-\frac{3}{10}=8\frac{10}{10}-\frac{3}{10}=8\frac{7}{10}$$
  6. $$3\frac{6}{17}-2\frac{7}{17}=(3-2)+(\frac{6}{17}-\frac{7}{17})=1-\frac{1}{17}=\frac{17}{17}-\frac{1}{17}=\frac{16}{17}$$
  7. $$23\frac{6}{19}-15\frac{16}{19}=(23-15)+(\frac{6}{19}-\frac{16}{19})=8-\frac{10}{19}=7\frac{19}{19}-\frac{10}{19}=7\frac{9}{19}$$
  8. $$17\frac{6}{17}-15\frac{9}{17}=(17-15)+(\frac{6}{17}-\frac{9}{17})=2-\frac{3}{17}=1\frac{17}{17}-\frac{3}{17}=1\frac{14}{17}$$
  9. $$5\frac{9}{23}-4\frac{15}{23}=(5-4)+(\frac{9}{23}-\frac{15}{23})=1-\frac{6}{23}=\frac{23}{23}-\frac{6}{23}=\frac{17}{23}$$
  10. $$10\frac{1}{9}-3\frac{5}{9}=(10-3)+(\frac{1}{9}-\frac{5}{9})=7-\frac{4}{9}=6\frac{9}{9}-\frac{4}{9}=6\frac{5}{9}$$
  11. $$12\frac{8}{10}-10\frac{9}{10}=(12-10)+(\frac{8}{10}-\frac{9}{10})=2-\frac{1}{10}=1\frac{10}{10}-\frac{1}{10}=1\frac{9}{10}$$
  12. $$5\frac{2}{7}-4\frac{5}{7}=(5-4)+(\frac{2}{7}-\frac{5}{7})=1-\frac{3}{7}=\frac{7}{7}-\frac{3}{7}=\frac{4}{7}$$
  13. $$2\frac{3}{5}+3\frac{4}{5}=(2+3)+(\frac{3}{5}+\frac{4}{5})=5+\frac{7}{5}=5+1\frac{2}{5}=6\frac{2}{5}$$
  14. $$11\frac{6}{7}+13\frac{5}{7}=(11+13)+(\frac{6}{7}+\frac{5}{7})=24+\frac{11}{7}=24+1\frac{4}{7}=25\frac{4}{7}$$
  15. $$8\frac{9}{16}-7\frac{5}{16}=(8-7)+(\frac{9}{16}-\frac{5}{16})=1+\frac{4}{16}=1\frac{1}{4}$$
  16. $$10\frac{5}{9}-4\frac{5}{9}=(10-4)+(\frac{5}{9}-\frac{5}{9})=6+0=6$$

Ответ: 1) 8; 2) $$6\frac{5}{21}$$; 3) $$9\frac{1}{17}$$; 4) $$16\frac{1}{3}$$; 5) $$8\frac{7}{10}$$; 6) $$\frac{16}{17}$$; 7) $$7\frac{9}{19}$$; 8) $$1\frac{14}{17}$$; 9) $$\frac{17}{23}$$; 10) $$6\frac{5}{9}$$; 11) $$1\frac{9}{10}$$; 12) $$\frac{4}{7}$$; 13) $$6\frac{2}{5}$$; 14) $$25\frac{4}{7}$$; 15) $$1\frac{1}{4}$$; 16) 6

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