Задание 158. Найдите значение выражения, представив обыкновенную дробь в виде десятичной. 1) \(\frac{1}{2}+1;2--0,5+1,2-1,7\) 3 6) -0.14- 5 11) 2.6\(\frac{1}{5}+2.3-7\) 11 2) 0.7+-+3.41-46 5 20 3 12) 11 -0.01- 2 1 3) :2- 20 1 8)1-0,7- 5 13)(\(\frac{5}{6}\)30- 4 5) 1 4) -22-10 25 12 9) :8- 25 14) 3.\(\frac{105}{50}+3.7-\) 1 5) 5,27-- 4 3 10)21-- 4 5) 45.1-(+0,5) =

1) \(\frac{1}{2} + 1.2 - 0.5 + 1.2 - 1.7 = 0.5 + 1.2 - 0.5 + 1.2 - 1.7 = 0.7\)

2) \(0.7 + \frac{1}{5} + 3.41 - 1.26 = 0.7 + 0.2 + 3.41 - 1.26 = 3.05\)

3) \(\frac{1}{20} : 2 = 0.05 : 2 = 0.025\)

4) \(\frac{1}{25} - 22 - 10 = 0.04 - 22 - 10 = -31.96\)

5) \(5.27 - \frac{1}{4} = 5.27 - 0.25 = 5.02\)

6) \(\frac{3}{5} - 0.14 = 0.6 - 0.14 = 0.46\)

7) \(\frac{11}{20} + 3.41 - 1.26 = 0.55 + 3.41 - 1.26 = 2.7\)

8) \(1\frac{1}{5} - 0.7 = 1.2 - 0.7 = 0.5\)

9) \(\frac{12}{25} : 8 = 0.48 : 8 = 0.06\)

10) \(21 \cdot \frac{3}{4} = 21 \cdot 0.75 = 15.75\)

11) \(2.6 \cdot \frac{1}{5} + 2.3 - 7 = 2.6 \cdot 0.2 + 2.3 - 7 = 0.52 + 2.3 - 7 = -4.18\)

12) \(\frac{3}{2} \cdot 11 - 0.01 = 1.5 \cdot 11 - 0.01 = 16.5 - 0.01 = 16.49\)

13) \((\frac{5}{6} - \frac{4}{5}) \cdot 30 = (\frac{25}{30} - \frac{24}{30}) \cdot 30 = \frac{1}{30} \cdot 30 = 1\)

14) \(3 \cdot \frac{105}{50} + 3.7 = 3 \cdot 2.1 + 3.7 = 6.3 + 3.7 = 10\)

15) \(45.1 \cdot (\frac{2}{5} + 0.5) = 45.1 \cdot (0.4 + 0.5) = 45.1 \cdot 0.9 = 40.59\)