Ықшамдаңыз: \(\frac{\cos^2\gamma}{1-\sin gamma}-\sin\gamma\).

\(\cos^2\gamma=1-\sin^2\gamma=(1-\sin\gamma)(1+\sin\gamma)\).

Сондықтан:

\[\frac{\cos^2\gamma}{1-\sin\gamma}-\sin\gamma=\frac{(1-\sin\gamma)(1+\sin\gamma)}{1-\sin\gamma}-\sin\gamma=1+\sin\gamma-\frac{}{}\sin\gamma=1.\]

Мұнда \(1-\sin\gamma
e0\).

Жауабы: \(1\).