Й) \(\frac\){\(\left\)\(4,5\cdot1\frac{2}{3}-6,75\right\)\(\cdot\)\(\frac{2}{3}\)}{\(\left\)\(3\frac{1}{3}\cdot0,3+5\frac{1}{3}\cdot1\frac{1}{8}\right\):2\(\frac{2}{3}\)}+\(\frac{1\frac{4}{11}\cdot0,22:0,3-0,96}\){\(\left\)\(0,2-\frac{3}{40}\right\)\(\cdot\)1,6}

Первая дробь:

\[\left(4.5\cdot1\frac23-6.75\right)\cdot\frac23=\left(7.5-6.75\right)\cdot\frac23=\frac12.\]

\[\left(3\frac13\cdot0.3+5\frac13\cdot1\frac18\right):2\frac23=(1+6):\frac83=\frac{21}{8}.\]

\[\frac{1/2}{21/8}=\frac4{21}.\]

Вторая дробь:

\[1\frac4{11}\cdot0.22:0.3-0.96=\frac{15}{11}\cdot\frac{11}{50}:\frac3{10}-\frac{24}{25}=1-\frac{24}{25}=\frac1{25}.\]

\[\left(0.2-\frac3{40}\right)\cdot1.6=\left(\frac15-\frac3{40}\right)\cdot\frac85=\frac15.\]

\[\frac{1/25}{1/5}=\frac15.\]

\[\frac4{21}+\frac15=\frac{20}{105}+\frac{21}{105}=\frac{41}{105}.\]

Ответ: \(\frac{41}{105}\).