10) \(y = \frac{2}{x^2 + 3}\)

D(f) = R. E(f) = (0, \frac{2}{3}]. f(0) = \frac{2}{0^2 + 3} = \frac{2}{3}. f(-1) = \frac{2}{(-1)^2 + 3} = \frac{2}{1 + 3} = \frac{2}{4} = \frac{1}{2}. f(10) = \frac{2}{10^2 + 3} = \frac{2}{100 + 3} = \frac{2}{103}.