24x5 8y3 16 y2 6x3

$$\frac{24x^5}{16y^2} \cdot \frac{8y^3}{6x^3} = \frac{24 \cdot 8 \cdot x^5 \cdot y^3}{16 \cdot 6 \cdot y^2 \cdot x^3} = \frac{192x^5y^3}{96x^3y^2} = 2x^{5-3}y^{3-2} = 2x^2y$$ Ответ: $$2x^2y$$