1) $$ \frac{x^2+4x+4}{x+2} = \frac{(x+2)^2}{x+2} = x+2 $$
4) $$ \frac{m-6}{m+6} - \frac{m+6}{m-6} = \frac{(m-6)^2 - (m+6)^2}{(m+6)(m-6)} = \frac{m^2-12m+36 - (m^2+12m+36)}{m^2-36} = \frac{-24m}{m^2-36} = 0 $$
$$-24m = 0$$
$$m = 0$$
Ответ: 1) $$x+2$$, 4) $$m=0$$