Давай решим каждое квадратное уравнение по порядку, используя дискриминант.
1) 2x² - 5x + 2 = 0
* a = 2, b = -5, c = 2
* D = b² - 4ac = (-5)² - 4 * 2 * 2 = 25 - 16 = 9
* √D = √9 = 3
* x₁ = (-b + √D) / (2a) = (5 + 3) / (2 * 2) = 8 / 4 = 2
* x₂ = (-b - √D) / (2a) = (5 - 3) / (2 * 2) = 2 / 4 = 0.5
2) 2x² - 7x - 4 = 0
* a = 2, b = -7, c = -4
* D = b² - 4ac = (-7)² - 4 * 2 * (-4) = 49 + 32 = 81
* √D = √81 = 9
* x₁ = (-b + √D) / (2a) = (7 + 9) / (2 * 2) = 16 / 4 = 4
* x₂ = (-b - √D) / (2a) = (7 - 9) / (2 * 2) = -2 / 4 = -0.5
3) 4x² - 3x - 1 = 0
* a = 4, b = -3, c = -1
* D = b² - 4ac = (-3)² - 4 * 4 * (-1) = 9 + 16 = 25
* √D = √25 = 5
* x₁ = (-b + √D) / (2a) = (3 + 5) / (2 * 4) = 8 / 8 = 1
* x₂ = (-b - √D) / (2a) = (3 - 5) / (2 * 4) = -2 / 8 = -0.25
4) -2x² + x + 15 = 0
* a = -2, b = 1, c = 15
* D = b² - 4ac = (1)² - 4 * (-2) * 15 = 1 + 120 = 121
* √D = √121 = 11
* x₁ = (-b + √D) / (2a) = (-1 + 11) / (2 * -2) = 10 / -4 = -2.5
* x₂ = (-b - √D) / (2a) = (-1 - 11) / (2 * -2) = -12 / -4 = 3
5) 6x² + 7x - 5 = 0
* a = 6, b = 7, c = -5
* D = b² - 4ac = (7)² - 4 * 6 * (-5) = 49 + 120 = 169
* √D = √169 = 13
* x₁ = (-b + √D) / (2a) = (-7 + 13) / (2 * 6) = 6 / 12 = 0.5
* x₂ = (-b - √D) / (2a) = (-7 - 13) / (2 * 6) = -20 / 12 = -5/3
Ответ: Решения уравнений найдены выше.