a) $$ \frac{4}{7} + (-\frac{2}{7}) = \frac{4}{7} - \frac{2}{7} = \frac{4-2}{7} = \frac{2}{7} $$
в) $$ \frac{9}{5} + (-\frac{8}{7}) = \frac{9}{5} - \frac{8}{7} = \frac{9 \cdot 7 - 8 \cdot 5}{35} = \frac{63 - 40}{35} = \frac{23}{35} $$
б) $$ \frac{7}{3} + (-\frac{4}{3}) = \frac{7}{3} - \frac{4}{3} = \frac{7-4}{3} = \frac{3}{3} = 1 $$
Ответ: a) $$\frac{2}{7}$$; в) $$\frac{23}{35}$$; б) 1