a) $$\left(\frac{4}{9} + \frac{2}{9}\right) \cdot \frac{9}{13} = \frac{4+2}{9} \cdot \frac{9}{13} = \frac{6}{9} \cdot \frac{9}{13} = \frac{2}{3} \cdot \frac{9}{13} = \frac{2 \cdot 3}{13} = \frac{6}{13}$$
Ответ: 6/13
б) $$\frac{2}{3} \cdot \left(\frac{9}{8} - \frac{3}{4}\right) = \frac{2}{3} \cdot \left(\frac{9}{8} - \frac{3 \cdot 2}{4 \cdot 2}\right) = \frac{2}{3} \cdot \left(\frac{9}{8} - \frac{6}{8}\right) = \frac{2}{3} \cdot \frac{9-6}{8} = \frac{2}{3} \cdot \frac{3}{8} = \frac{2}{8} = \frac{1}{4}$$
Ответ: 1/4
в) $$\left(\frac{9}{11} - \frac{4}{11}\right) \cdot \frac{11}{5} = \frac{9-4}{11} \cdot \frac{11}{5} = \frac{5}{11} \cdot \frac{11}{5} = 1$$
Ответ: 1
г) $$2 \cdot \frac{1}{8} + \frac{7}{12} \cdot \frac{3}{7} = \frac{2}{8} + \frac{7 \cdot 3}{12 \cdot 7} = \frac{1}{4} + \frac{3}{12} = \frac{1}{4} + \frac{1}{4} = \frac{1+1}{4} = \frac{2}{4} = \frac{1}{2}$$
Ответ: 1/2
д) $$\left(\frac{2}{3}\right)^2 + \frac{13}{21} \cdot \frac{7}{26} - \frac{5}{18} = \frac{4}{9} + \frac{13 \cdot 7}{21 \cdot 26} - \frac{5}{18} = \frac{4}{9} + \frac{1 \cdot 1}{3 \cdot 2} - \frac{5}{18} = \frac{4}{9} + \frac{1}{6} - \frac{5}{18} = \frac{4 \cdot 2}{9 \cdot 2} + \frac{1 \cdot 3}{6 \cdot 3} - \frac{5}{18} = \frac{8}{18} + \frac{3}{18} - \frac{5}{18} = \frac{8+3-5}{18} = \frac{6}{18} = \frac{1}{3}$$
Ответ: 1/3
e) $$\left(\frac{3}{7} - \frac{1}{7}\right) \cdot \frac{49}{16} + \left(\frac{1}{2}\right)^3 = \frac{3-1}{7} \cdot \frac{49}{16} + \frac{1}{8} = \frac{2}{7} \cdot \frac{49}{16} + \frac{1}{8} = \frac{1 \cdot 7}{1 \cdot 8} + \frac{1}{8} = \frac{7}{8} + \frac{1}{8} = \frac{7+1}{8} = \frac{8}{8} = 1$$
Ответ: 1