Выполним задание.
1. Вычислите:
а) 50 ⋅ (-1,04) = -52
б) -1,4 ⋅ (-0,2) = 0,28
в) \[-2\frac{1}{7} \cdot 4,2 = - \frac{15}{7} \cdot \frac{42}{10} = - \frac{15 \cdot 6}{10} = - \frac{90}{10} = -9\]
г) \[-3\frac{1}{9} \cdot (-2\frac{1}{7}) = - \frac{28}{9} \cdot (- \frac{15}{7}) = \frac{4 \cdot 5}{3} = \frac{20}{3} = 6\frac{2}{3}\]
2. Решите уравнение:
а) x : (-2,2) = 3
x = 3 ⋅ (-2,2)
x = -6,6
б) \[(x-\frac{1}{7}) : (-4\frac{7}{12}) = \frac{4}{11}\]
\[(x-\frac{1}{7}) : (-\frac{55}{12}) = \frac{4}{11}\]
\[x-\frac{1}{7} = \frac{4}{11} \cdot (-\frac{55}{12})\]
\[x-\frac{1}{7} = - \frac{4 \cdot 5}{12}\]
\[x-\frac{1}{7} = - \frac{5}{3}\]
\[x = - \frac{5}{3} + \frac{1}{7}\]
\[x = - \frac{35}{21} + \frac{3}{21}\]
\[x = - \frac{32}{21} = -1\frac{11}{21}\]
3. Найдите значение выражения:
а) 7 ⋅ (-2,5) - (-4) ⋅ (-0,6) + (-6) ⋅ (-1,2) = -17,5 - 2,4 + 7,2 = -12,7
б) \[(-1\frac{3}{7})^2 \cdot (-12\frac{1}{4}) + 15\frac{2}{3} = (-\frac{10}{7})^2 \cdot (-\frac{49}{4}) + \frac{47}{3} = \frac{100}{49} \cdot (-\frac{49}{4}) + \frac{47}{3} = -25 + \frac{47}{3} = \frac{-75 + 47}{3} = - \frac{28}{3} = -9\frac{1}{3}\]
Ответ: смотри решение