а) Для \(p^2\):
\(p = -4\): \((-4)^2 = 16\)
\(p = \frac{1}{9}\): \((\frac{1}{9})^2 = \frac{1}{81}\)
\(p = 0,6\): \((0,6)^2 = 0,36\)
\(p = -0,8\): \((-0,8)^2 = 0,64\)
\(p = -2 \frac{1}{3} = -\frac{7}{3}\): \((-\frac{7}{3})^2 = \frac{49}{9} = 5 \frac{4}{9}\)
\(p = 3 \frac{1}{5} = \frac{16}{5}\): \((\frac{16}{5})^2 = \frac{256}{25} = 10 \frac{6}{25}\)
б) Для \(b^3\):
\(b = -2\): \((-2)^3 = -8\)
\(b = -\frac{2}{3}\): \((-\frac{2}{3})^3 = -\frac{8}{27}\)
\(b = 0,1 = \frac{1}{10}\): \((\frac{1}{10})^3 = \frac{1}{1000} = 0,001\)
\(b = -0,1 = -\frac{1}{10}\): \((-\frac{1}{10})^3 = -\frac{1}{1000} = -0,001\)
\(b = -1 \frac{1}{5} = -\frac{6}{5}\): \((-\frac{6}{5})^3 = -\frac{216}{125} = -1 \frac{91}{125}\)
\(b = 2 \frac{1}{2} = \frac{5}{2}\): \((\frac{5}{2})^3 = \frac{125}{8} = 15 \frac{5}{8}\)