a) 4 \frac{2}{15} – 3 \frac{3}{10} – 2 \frac{1}{6}
= \frac{62}{15} - \frac{33}{10} - \frac{13}{6}
= \frac{124}{30} - \frac{99}{30} - \frac{65}{30}
= \frac{124 - 99 - 65}{30}
= \frac{-40}{30}
= -\frac{4}{3}
= -1 \frac{1}{3}
б) 7 \frac{5}{21} – 14 \frac{1}{7} + 6 \frac{1}{14}
= \frac{152}{21} - \frac{99}{7} + \frac{85}{14}
= \frac{304}{42} - \frac{594}{42} + \frac{255}{42}
= \frac{304 - 594 + 255}{42}
= \frac{-35}{42}
= -\frac{5}{6}
= -\frac{5}{6}
в) 24 \frac{2}{35} – 18 \frac{5}{14} – 5 \frac{3}{10}
= \frac{842}{35} - \frac{257}{14} - \frac{53}{10}
= \frac{1684}{70} - \frac{1285}{70} - \frac{371}{70}
= \frac{1684 - 1285 - 371}{70}
= \frac{28}{70}
= \frac{2}{5}
= \frac{2}{5}
г) 1 \frac{2}{9} + 2 \frac{5}{6} – 35 \frac{1}{5}
= \frac{11}{9} + \frac{17}{6} - \frac{176}{5}
= \frac{110}{90} + \frac{255}{90} - \frac{3168}{90}
= \frac{110 + 255 - 3168}{90}
= \frac{-2803}{90}
= -31 \frac{13}{90}
= -31 \frac{13}{90}