Ответ:
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- \(\left(\frac{17}{10}-\frac{1}{20}\right)\cdot\frac{2}{15}=\left(\frac{34}{20}-\frac{1}{20}\right)\cdot\frac{2}{15}=\frac{33}{20}\cdot\frac{2}{15}=\frac{11}{50}\).
- \(\left(\frac{5}{22}-\frac{8}{11}\right)\cdot\frac{11}{5}=\left(\frac{5}{22}-\frac{16}{22}\right)\cdot\frac{11}{5}=-\frac{1}{2}\cdot\frac{11}{5}=-\frac{11}{10}\).
- \(\left(\frac{5}{26}-\frac{3}{25}\right)\cdot\frac{13}{2}=\left(\frac{125}{650}-\frac{78}{650}\right)\cdot\frac{13}{2}=\frac{47}{650}\cdot\frac{13}{2}=\frac{47}{100}\).
- \(\left(\frac{10}{13}+\frac{15}{4}\right)\cdot\frac{26}{5}=\frac{235}{52}\cdot\frac{26}{5}=\frac{47}{2}\).
- \(\left(\frac{17}{26}+\frac{11}{13}\right)\cdot\frac{17}{6}=\left(\frac{17}{26}+\frac{22}{26}\right)\cdot\frac{17}{6}=\frac{3}{2}\cdot\frac{17}{6}=\frac{17}{4}\).
- \(\left(\frac{11}{12}+\frac{11}{20}\right)\cdot\frac{15}{8}=\left(\frac{55}{60}+\frac{33}{60}\right)\cdot\frac{15}{8}=\frac{22}{15}\cdot\frac{15}{8}=\frac{11}{4}\).
- \(\left(\frac{3}{4}-\frac{1}{6}\right)\cdot3=\left(\frac{9}{12}-\frac{2}{12}\right)\cdot3=\frac{7}{12}\cdot3=\frac{7}{4}\).
- \(\left(\frac{2}{5}+\frac{13}{15}\right)\cdot6=\left(\frac{6}{15}+\frac{13}{15}\right)\cdot6=\frac{19}{15}\cdot6=\frac{38}{5}\).
- \(\left(\frac{3}{8}-\frac{1}{20}\right)\cdot10=\left(\frac{15}{40}-\frac{2}{40}\right)\cdot10=\frac{13}{40}\cdot10=\frac{13}{4}\).
Ответ: 1) \(\frac{11}{50}\); 2) \(-\frac{11}{10}\); 3) \(\frac{47}{100}\); 4) \(\frac{47}{2}\); 5) \(\frac{17}{4}\); 6) \(\frac{11}{4}\); 7) \(\frac{7}{4}\); 8) \(\frac{38}{5}\); 9) \(\frac{13}{4}\).
