83. Вычислите значение выражения:
1) $$(5\frac{5}{6}-1\frac{1}{3}):(7\frac{7}{12}-2\frac{1}{4})\cdot 1,25=(\frac{5 \cdot 6+5}{6}-\frac{1 \cdot 3+1}{3}):(\frac{7 \cdot 12+7}{12}-\frac{2 \cdot 4+1}{4}) \cdot 1,25=(\frac{30+5}{6}-\frac{3+1}{3}):(\frac{84+7}{12}-\frac{8+1}{4}) \cdot 1,25=(\frac{35}{6}-\frac{4}{3}):(\frac{91}{12}-\frac{9}{4}) \cdot 1,25=(\frac{35}{6}-\frac{4 \cdot 2}{3 \cdot 2}):(\frac{91}{12}-\frac{9 \cdot 3}{4 \cdot 3}) \cdot 1,25=(\frac{35}{6}-\frac{8}{6}):(\frac{91}{12}-\frac{27}{12}) \cdot 1,25=\frac{27}{6}:\frac{64}{12} \cdot 1,25=\frac{27}{6} \cdot \frac{12}{64} \cdot 1,25=\frac{9 \cdot 3}{6} \cdot \frac{6 \cdot 2}{64} \cdot 1,25=\frac{9 \cdot 2}{64} \cdot 1,25=\frac{18}{64} \cdot 1,25=\frac{9}{32} \cdot 1,25=\frac{9}{32} \cdot \frac{125}{100}=\frac{9}{32} \cdot \frac{5 \cdot 25}{4 \cdot 25}=\frac{9}{32} \cdot \frac{5}{4}=\frac{45}{128}$$
Ответ: $$\frac{45}{128}$$
2) $$(3\frac{3}{5}-7\frac{1}{2}:27+1\frac{2}{9}):(3\frac{1}{6}-1\frac{1}{4})=(\frac{3 \cdot 5+3}{5}-\frac{7 \cdot 2+1}{2}:27+\frac{1 \cdot 9+2}{9}):(\frac{3 \cdot 6+1}{6}-\frac{1 \cdot 4+1}{4})=(\frac{15+3}{5}-\frac{14+1}{2}:27+\frac{9+2}{9}):(\frac{18+1}{6}-\frac{4+1}{4})=(\frac{18}{5}-\frac{15}{2}:27+\frac{11}{9}):(\frac{19}{6}-\frac{5}{4})=(\frac{18}{5}-\frac{15}{2} \cdot \frac{1}{27}+\frac{11}{9}):(\frac{19 \cdot 2}{6 \cdot 2}-\frac{5 \cdot 3}{4 \cdot 3})=(\frac{18}{5}-\frac{5 \cdot 3}{2} \cdot \frac{1}{9 \cdot 3}+\frac{11}{9}):(\frac{38}{12}-\frac{15}{12})=(\frac{18}{5}-\frac{5}{2} \cdot \frac{1}{9}+\frac{11}{9}):\frac{23}{12}=(\frac{18}{5}-\frac{5}{18}+\frac{11}{9}):\frac{23}{12}=(\frac{18 \cdot 18}{5 \cdot 18}-\frac{5 \cdot 5}{18 \cdot 5}+\frac{11 \cdot 10}{9 \cdot 10}):\frac{23}{12}=(\frac{324}{90}-\frac{25}{90}+\frac{110}{90}):\frac{23}{12}=\frac{409}{90}:\frac{23}{12}=\frac{409}{90} \cdot \frac{12}{23}=\frac{409}{15 \cdot 6} \cdot \frac{2 \cdot 6}{23}=\frac{409}{15} \cdot \frac{2}{23}=\frac{818}{345}=2\frac{128}{345}$$
Ответ: $$2\frac{128}{345}$$