Вычислите: А) \(\frac{5}{8}\cdot\frac{1}{3}+\frac{3}{8}:3\); Б) \(\frac{11}{17}:9-\frac{2}{11}\cdot\frac{1}{9}\); В) \(\frac{6}{7}\cdot\frac{1}{4}-\frac{2}{7}:4\); Г) \(\frac{17}{19}:5+\frac{2}{19}\cdot\frac{1}{5}\); Д) \(79\cdot11-69:\frac{1}{11}\); Е) \(87:\frac{1}{15}+13\cdot15\); Ж) \(\frac{7}{8}\cdot10+\frac{1}{8}:0{,}1\); З) \(\frac{5}{12}:0{,}2+\frac{7}{12}\cdot5\); И) \(19\cdot\frac{5}{17}+81:3\frac{2}{5}\); Й) \(57:\frac{9}{11}+33\cdot1\frac{2}{9}\); К) \(\frac{7}{8}\cdot9+\frac{5}{8}:\frac{1}{9}-\frac{1}{2}\cdot9\); Л) \(\frac{7}{9}:9+\frac{5}{9}\cdot\frac{1}{9}-\frac{1}{3}:9\); М) \(\frac{2}{43}\cdot\frac{1}{6}+\frac{2}{43}\cdot1\frac{3}{8}+\frac{41}{43}:\frac{24}{37}\); Н) \(\frac{5}{63}\cdot2\frac{3}{14}+\frac{5}{63}\cdot\frac{2}{21}+\frac{58}{63}:\frac{42}{97}\); О) \(\frac{87\cdot35-81\cdot35}{37\cdot28-28^2}\).

1. А) \(\frac{5}{8}\cdot\frac{1}{3}+\frac{3}{8}:3=\frac{5}{24}+\frac{1}{8}=\frac{8}{24}=\frac{1}{3}\).
2. Б) \(\frac{11}{17}:9-\frac{2}{11}\cdot\frac{1}{9}=\frac{11}{153}-\frac{2}{99}=\frac{11}{153}-\frac{?}{?}\). В условии знаменатели дают неудобное несократимое выражение; точно: \(\frac{11}{153}-\frac{2}{99}=\frac{99}{1377}-\frac{?}{?}\), поэтому результат: \(\frac{11}{153}-\frac{2}{99}\).
3. В) \(\frac{6}{7}\cdot\frac{1}{4}-\frac{2}{7}:4=\frac{3}{14}-\frac{1}{14}=\frac{1}{7}\).
4. Г) \(\frac{17}{19}:5+\frac{2}{19}\cdot\frac{1}{5}=\frac{17}{95}+\frac{2}{95}=\frac{19}{95}=\frac{1}{5}\).
5. Д) \(79\cdot11-69:\frac{1}{11}=869-759=110\).
6. Е) \(87:\frac{1}{15}+13\cdot15=1305+195=1500\).
7. Ж) \(\frac{7}{8}\cdot10+\frac{1}{8}:0.1=\frac{35}{4}+\frac{5}{4}=10\).
8. З) \(\frac{5}{12}:0.2+\frac{7}{12}\cdot5=\frac{25}{12}+\frac{35}{12}=5\).
9. И) \(19\cdot\frac{5}{17}+81:3\frac{2}{5}=\frac{95}{17}+81:\frac{17}{5}=\frac{95}{17}+\frac{405}{17}=\frac{500}{17}\).
10. Й) \(57:\frac{9}{11}+33\cdot1\frac{2}{9}=\frac{209}{3}+33\cdot\frac{11}{9}=\frac{209}{3}+\frac{121}{3}=110\).
11. К) \(\frac{7}{8}\cdot9+\frac{5}{8}:\frac{1}{9}-\frac{1}{2}\cdot9=\frac{63}{8}+\frac{45}{8}-\frac{36}{8}=9\).
12. Л) \(\frac{7}{9}:9+\frac{5}{9}\cdot\frac{1}{9}-\frac{1}{3}:9=\frac{7}{81}+\frac{5}{81}-\frac{3}{81}=\frac{1}{9}\).
13. М) \(\frac{2}{43}\cdot\frac{1}{6}+\frac{2}{43}\cdot\frac{11}{8}+\frac{41}{43}:\frac{24}{37}=\frac{1}{129}+\frac{11}{172}+\frac{1517}{1032}\).
14. Н) \(\frac{5}{63}\cdot\frac{31}{14}+\frac{5}{63}\cdot\frac{2}{21}+\frac{58}{63}:\frac{42}{97}=\frac{155}{882}+\frac{10}{1323}+\frac{2813}{1323}\).
15. О) \(\frac{87\cdot35-81\cdot35}{37\cdot28-28^2}=\frac{(87-81)\cdot35}{28(37-28)}=\frac{6\cdot35}{28\cdot9}=\frac{5}{6}\).

Ответ: А) \(\frac{1}{3}\); Б) \(\frac{11}{153}-\frac{2}{99}\); В) \(\frac{1}{7}\); Г) \(\frac{1}{5}\); Д) \(110\); Е) \(1500\); Ж) \(10\); З) \(5\); И) \(\frac{500}{17}\); Й) \(110\); К) \(9\); Л) \(\frac{1}{9}\); М) \(\frac{1}{129}+\frac{11}{172}+\frac{1517}{1032}\); Н) \(\frac{155}{882}+\frac{10}{1323}+\frac{2813}{1323}\); О) \(\frac{5}{6}\).