Вычислите: а) \(7\frac{3}{2}+1\frac{15}{6}\); б) \(2\frac{3}{5}+\frac{1}{15}\); в) \(1\frac{1}{8}+2\frac{3}{5}\); г) \(6\frac{3}{10}-\frac{11}{15}\); д) \(7\frac{5}{12}-3\frac{2}{9}\); е) \(5\frac{7}{8}+2\frac{5}{12}\).

1. \(7\frac{3}{2}+1\frac{15}{6}=8\frac{3}{2}+\frac{15}{6}=8+\frac{3}{2}+\frac{5}{2}=11\frac{1}{2}\).
2. \(2\frac{3}{5}+\frac{1}{15}=2+\frac{9}{15}+\frac{1}{15}=2\frac{10}{15}=2\frac{2}{3}\).
3. \(1\frac{1}{8}+2\frac{3}{5}=3+\frac{5}{40}+\frac{24}{40}=3\frac{29}{40}\).
4. \(6\frac{3}{10}-\frac{11}{15}=6+\frac{9}{30}-\frac{22}{30}=5\frac{17}{30}\).
5. \(7\frac{5}{12}-3\frac{2}{9}=4+\frac{15}{36}-\frac{8}{36}=4\frac{7}{36}\).
6. \(5\frac{7}{8}+2\frac{5}{12}=7+\frac{42}{48}+\frac{20}{48}=8\frac{1}{48}\).

Ответ: а) \(11\frac{1}{2}\); б) \(2\frac{2}{3}\); в) \(3\frac{29}{40}\); г) \(5\frac{17}{30}\); д) \(4\frac{7}{36}\); е) \(8\frac{1}{48}\).