Вычислите: 1) \((1,2:36+1,2:0,25-1\frac{5}{16}):\frac{169}{24}\); 2) \(((\frac{7}{9}-\frac{47}{72}):1,25+\frac{7}{40}):(0,358-0,108)\cdot1,6-\frac{19}{25}\); 3) \(\frac{(0,5:1,25+\frac{7}{5}:1\frac{4}{7}-\frac{3}{11})\cdot3}{(1,5+\frac{1}{4}):18\frac{1}{3}}\).

\[1,2:36+1,2:0,25-1\frac{5}{16}=\frac{1}{30}+\frac{24}{5}-\frac{21}{16}=\frac{169}{120}.\] Тогда \[\frac{169}{120}:\frac{169}{24}=\frac{1}{5}.\]

Ответ: \(\frac{1}{5}\).

\[\frac{7}{9}-\frac{47}{72}=\frac{56-47}{72}=\frac{1}{8},\qquad \frac{1}{8}:1,25=\frac{1}{10}.\] Поэтому \[\left(\frac{1}{10}+\frac{7}{40}\right)=\frac{11}{40}.\] Далее \[0,358-0,108=0,25,\qquad 0,25\cdot1,6-\frac{19}{25}=0,4-0,76=-0,36.\] Следовательно, \[\frac{11}{40}:(-0,36)=-\frac{55}{72}.\]

Ответ: \(-\frac{55}{72}\).

\[0,5:1,25=\frac{2}{5},\qquad \frac{7}{5}:1\frac{4}{7}=\frac{7}{5}:\frac{11}{7}=\frac{49}{55}.\] Числитель: \[\left(\frac{2}{5}+\frac{49}{55}-\frac{3}{11}\right)\cdot3=\left(\frac{22+49-15}{55}\right)\cdot3=\frac{168}{55}.\] Знаменатель: \[\left(1,5+\frac14\right):18\frac13=\frac74:\frac{55}{3}=\frac{21}{220}.\] Тогда \[\frac{168}{55}:\frac{21}{220}=32.\]

Ответ: \(32\).