Вычислите (1-2): 1. a) \(\frac{3}{7}+(-\frac{9}{14})\); 6) \(-\frac{3}{10}-\frac{1}{15}\); в) \(-\frac{12}{35} \cdot \frac{15}{16}\); г) \(\frac{14}{9}:(-\frac{16}{15})\). 2. \(-\frac{8}{25} \cdot \frac{15}{14} - \frac{11}{48}:(-\frac{7}{8})\).

1. a) \(\frac{3}{7}+(-\frac{9}{14})\) = \(\frac{3}{7}-\frac{9}{14}\) = \(\frac{6}{14}-\frac{9}{14}\) = \(\frac{-3}{14}\)

1. б) \(-\frac{3}{10}-\frac{1}{15}\) = \(\frac{-9}{30}-\frac{2}{30}\) = \(\frac{-11}{30}\)

1. в) \(-\frac{12}{35} \cdot \frac{15}{16}\) = \(-\frac{3}{7} \cdot \frac{3}{4}\) = \(\frac{-9}{28}\)

1. г) \(\frac{14}{9}:(-\frac{16}{15})\) = \(\frac{14}{9} \cdot (-\frac{15}{16})\) = \(\frac{7}{3} \cdot (-\frac{5}{8})\) = \(\frac{-35}{24}\)

2. \(-\frac{8}{25} \cdot \frac{15}{14} - \frac{11}{48}:(-\frac{7}{8})\) = \(-\frac{4}{5} \cdot \frac{3}{7} - \frac{11}{48} \cdot (-\frac{8}{7})\) = \(-\frac{12}{35} + \frac{11}{42} \) = \(-\frac{72}{210} + \frac{55}{210} \) = \(\frac{-17}{210}\)