9. Вычислим:
$$ (\frac{2}{3} \cdot \sqrt{36})^2 + 2(\sqrt{5})^2 + 15 \cdot \sqrt{11 \frac{14}{25}} = (\frac{2}{3} \cdot 6)^2 + 2 \cdot 5 + 15 \cdot \sqrt{\frac{11 \cdot 25 + 14}{25}} = (2 \cdot 2)^2 + 10 + 15 \cdot \sqrt{\frac{275 + 14}{25}} = 4^2 + 10 + 15 \cdot \sqrt{\frac{289}{25}} = 16 + 10 + 15 \cdot \frac{17}{5} = 26 + 3 \cdot 17 = 26 + 51 = 77 $$
Ответ: 77