2log₂ 6 + log₂ $$\frac{35}{9}$$ − log₂ 35 = log₂ 6² + log₂ $$\frac{35}{9}$$ − log₂ 35 = log₂ 36 + log₂ $$\frac{35}{9}$$ − log₂ 35 = log₂ (36 × $$\frac{35}{9}$$ ) − log₂ 35 = log₂ (4 × 35) − log₂ 35 = log₂ (4 × 35 / 35) = log₂ 4 = log₂ 2² = 2
Ответ: в) 2