Решения заданий Вариант 3:
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$$y = 7x + x^4$$
$$y' = 7 + 4x^3$$
Ответ: $$y' = 7 + 4x^3$$
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$$y = 3x^7 + 10x^2 - 13$$
$$y' = 21x^6 + 20x$$
Ответ: $$y' = 21x^6 + 20x$$
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$$y = 4x + \sqrt{x}$$
$$y = 4x + x^{\frac{1}{2}}$$
$$y' = 4 + \frac{1}{2}x^{-\frac{1}{2}}$$
$$y' = 4 + \frac{1}{2\sqrt{x}}$$
Ответ: $$y' = 4 + \frac{1}{2\sqrt{x}}$$
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$$y = \frac{1}{x} + 3x^3 - 35$$
$$y = x^{-1} + 3x^3 - 35$$
$$y' = -x^{-2} + 9x^2$$
$$y' = -\frac{1}{x^2} + 9x^2$$
Ответ: $$y' = -\frac{1}{x^2} + 9x^2$$
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$$y = -\frac{6}{x^8} - ctgx$$
$$y = -6x^{-8} - ctgx$$
$$y' = 48x^{-9} + \frac{1}{sin^2x}$$
$$y' = \frac{48}{x^9} + \frac{1}{sin^2x}$$
Ответ: $$y' = \frac{48}{x^9} + \frac{1}{sin^2x}$$
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$$y = \sqrt{x} - 3cosx$$
$$y = x^{\frac{1}{2}} - 3cosx$$
$$y' = \frac{1}{2}x^{-\frac{1}{2}} + 3sinx$$
$$y' = \frac{1}{2\sqrt{x}} + 3sinx$$
Ответ: $$y' = \frac{1}{2\sqrt{x}} + 3sinx$$
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$$y = -\frac{4}{x^5} - sinx$$
$$y = -4x^{-5} - sinx$$
$$y' = 20x^{-6} - cosx$$
$$y' = \frac{20}{x^6} - cosx$$
Ответ: $$y' = \frac{20}{x^6} - cosx$$
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$$y = (x^9 - 1)(10 + x^2)$$
$$y = x^{11} + 10x^9 - x^2 - 10$$
$$y' = 11x^{10} + 90x^8 - 2x$$
Ответ: $$y' = 11x^{10} + 90x^8 - 2x$$
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$$y = \sqrt{x}(3x - 4)$$
$$y = 3x^{\frac{3}{2}} - 4x^{\frac{1}{2}}$$
$$y' = \frac{9}{2}x^{\frac{1}{2}} - 2x^{-\frac{1}{2}}$$
$$y' = \frac{9}{2}\sqrt{x} - \frac{2}{\sqrt{x}}$$
Ответ: $$y' = \frac{9}{2}\sqrt{x} - \frac{2}{\sqrt{x}}$$
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$$y = x^4 sinx$$
$$y' = 4x^3 sinx + x^4 cosx$$
Ответ: $$y' = 4x^3 sinx + x^4 cosx$$
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$$y = (\frac{2}{x} - 5)(3x + 7)$$
$$y = (2x^{-1} - 5)(3x + 7)$$
$$y = 6 - 15x - 35 + 14x^{-1}$$
$$y = -15x - 29 + 14x^{-1}$$
$$y' = -15 - 14x^{-2}$$
$$y' = -15 - \frac{14}{x^2}$$
Ответ: $$y' = -15 - \frac{14}{x^2}$$
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$$y = \frac{5x^3}{2x - 7}$$
$$y' = \frac{15x^2(2x - 7) - 5x^3 \cdot 2}{(2x - 7)^2}$$
$$y' = \frac{30x^3 - 105x^2 - 10x^3}{(2x - 7)^2}$$
$$y' = \frac{20x^3 - 105x^2}{(2x - 7)^2}$$
$$y' = \frac{5x^2(4x - 21)}{(2x - 7)^2}$$
Ответ: $$y' = \frac{5x^2(4x - 21)}{(2x - 7)^2}$$
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$$y = \frac{-2\sqrt{x}}{x^6 - 2}$$
$$y = \frac{-2x^{\frac{1}{2}}}{x^6 - 2}$$
$$y' = \frac{-x^{-\frac{1}{2}}(x^6 - 2) + 2x^{\frac{1}{2}} \cdot 6x^5}{(x^6 - 2)^2}$$
$$y' = \frac{\frac{-x^6 + 2}{\sqrt{x}} + 12x^{\frac{11}{2}}}{(x^6 - 2)^2}$$
$$y' = \frac{\frac{-x^6 + 2 + 12x^{12}}{\sqrt{x}}}{(x^6 - 2)^2}$$
$$y' = \frac{-x^6 + 2 + 12x^{12}}{\sqrt{x}(x^6 - 2)^2}$$
Ответ: $$y' = \frac{12x^{12} - x^6 + 2}{\sqrt{x}(x^6 - 2)^2}$$
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$$y = \frac{tgx}{2x^2}$$
$$y = \frac{1}{2} \cdot \frac{tgx}{x^2}$$
$$y' = \frac{\frac{1}{cos^2x} \cdot x^2 - tgx \cdot 2x}{2x^4}$$
$$y' = \frac{\frac{x^2}{cos^2x} - 2x tgx}{2x^4}$$
Ответ: $$y' = \frac{\frac{x^2}{cos^2x} - 2x tgx}{2x^4}$$