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МатематикаВопрос:
30) \(-36v^2 + \frac{1}{4}q^{10} = \)
Ответ:
\((\frac{1}{2}q^5 - 6v)(\frac{1}{2}q^5 + 6v)\)
Похожие
- 1) \(x^2 - y^2 = \)
- 2) \(a^2 - h^2 = \)
- 3) \(c^2 - 3^2 = \)
- 4) \(4^2 - p^2 = \)
- 5) \(25 - b^2 = \)
- 6) \(n^2 - 1 = \)
- 7) \(m^2 - (3x)^2 = \)
- 8) \((2a)^2 - y^2 = \)
- 9) \(16k^2 - 25 = \)
- 10) \(100 - 49p^2 = \)
- 11) \(36h^2 - 1 = \)
- 12) \(0.64m^2 - 1 = \)
- 13) \(0.09x^2 - 81y^2 = \)
- 14) \(1 - 400y^2 = \)
- 15) \(49h^2 - 0.04c^2 = \)
- 16) \(0.01p^2 - 900t^2 = \)
- 17) \(121s^2 - 225a^2 = \)
- 18) \(1.44q^2 - 25c^2 = \)
- 19) \(196m^2 - 0.36n^2 = \)
- 20) \(x^2y^2 - 4 = \)
- 21) \(16a^4 - 9b^2 = \)
- 22) \(36p^6 - n^2m^{10} = \)
- 23) \(169k^4 - 4p^6 = \)
- 24) \(0.09a^2 - 100b^4 = \)
- 25) \(\frac{1}{4}x^2 - \frac{4}{9}y^2 = \)
- 26) \(\frac{25}{64}n^2 - \frac{1}{9}m^2 = \)
- 27) \(\frac{4}{49}k^2 - \frac{1}{36}p^2 = \)
- 28) \(0.64x^2 - \frac{1}{64}y^2 = \)
- 29) \(-1 + 4p^{100} = \)
- 30) \(-36v^2 + \frac{1}{4}q^{10} = \)
- 31) \(a^{10}b^{10} - c^{10}e^{20} = \)
- 32) \(-0.64k^{10} + 25n^{14} = \)
