a) \frac{6ab}{12bc} = \frac{a}{2c}
б) \frac{15xyz}{-5xz} = -3y
в) \frac{-27a^{2}b}{-9ab^{2}} = \frac{3a}{b}
г) \frac{-18cdk^{2}}{6c^{2}d^{2}k} = \frac{-3k}{cd}
д) \frac{-0,25a^{2}b^{3}}{20a^{3}b^{3}} = -\frac{1}{80a}
е) \frac{4,8mn^{2}k^{3}}{-1,6m^{2}k^{2}n} = -\frac{3nk}{m}
ж) \frac{0,12 \cdot 35x^{3}y^{4}}{0,7 \cdot 30x^{4}y^{3}} = \frac{0,12 \cdot 35}{0,7 \cdot 30} \cdot \frac{x^{3}y^{4}}{x^{4}y^{3}} = \frac{4,2}{21} \cdot \frac{y}{x} = \frac{1}{5} \cdot \frac{y}{x} = \frac{y}{5x}
з) \frac{-0,44 \cdot 13a^{3}b^{2}c^{4}}{-0,143 \cdot a^{2}bc^{3}} = \frac{0,44 \cdot 13}{0,143} \cdot \frac{a^{3}b^{2}c^{4}}{a^{2}bc^{3}} = \frac{5,72}{0,143} \cdot abc = 40abc
Ответ: a) \frac{a}{2c}; б) -3y; в) \frac{3a}{b}; г) \frac{-3k}{cd}; д) -\frac{1}{80a}; е) -\frac{3nk}{m}; ж) \frac{y}{5x}; з) 40abc