2. Упростите выражение: 3π 2.1 sin (3-α) π cos (-α) 2.2 2.3 tg (π +α) 2.4 ctg (+α) 2 2.5 sin (π-α) π 2.6 cos (a-1) 2 2.7 tg (2π-α) 2.8 ctg (π - α) 2.9 sin (π + α) 2.10 cos (π - α) 2.11 tg(+α) 2 3π 2.12 ctg (-a) 2 2.13 sin (α – π) 3π 2.14 cos(-a) 3π 2.15 tg(3+a) 2 2.16 ctg (2π + α) 2

Ответ: упрощенные выражения ниже

1. 2.1 \[\sin(\frac{3\pi}{2} - \alpha) = -\cos(\alpha)\]
2. 2.2 \[\cos(\frac{\pi}{2} - \alpha) = \sin(\alpha)\]
3. 2.3 \[\tan(\pi + \alpha) = \tan(\alpha)\]
4. 2.4 \[\cot(\frac{\pi}{2} + \alpha) = -\tan(\alpha)\]
5. 2.5 \[\sin(\pi - \alpha) = \sin(\alpha)\]
6. 2.6 \[\cos(\alpha - \frac{\pi}{2}) = \sin(\alpha)\]
7. 2.7 \[\tan(2\pi - \alpha) = -\tan(\alpha)\]
8. 2.8 \[\cot(\pi - \alpha) = -\cot(\alpha)\]
9. 2.9 \[\sin(\pi + \alpha) = -\sin(\alpha)\]
10. 2.10 \[ \cos(\pi - \alpha) = -\cos(\alpha)\]
11. 2.11 \[ \tan(\frac{3\pi}{2}+\alpha) = -ctg(\alpha)\]
12. 2.12 \[ ctg(\frac{3\pi}{2}-\alpha) = tg(\alpha)\]
13. 2.13 \[ sin(\alpha - \pi) = -sin(\pi - \alpha) = -sin(\alpha)\]
14. 2.14 \[ cos(\frac{3\pi}{2}-\alpha) = -sin(\alpha)\]
15. 2.15 \[ tg(\frac{3\pi}{2}+\alpha) = -ctg(\alpha)\]
16. 2.16 \[ ctg(2\pi+\alpha) = ctg(\alpha)\]

Ответ: упрощенные выражения выше