\( (\sqrt{18} + \sqrt{3})\sqrt{2} = \sqrt{18} \cdot \sqrt{2} + \sqrt{3} \cdot \sqrt{2} \)
\( \sqrt{18} = \sqrt{9 \cdot 2} = 3\sqrt{2} \)
\( \sqrt{3} \cdot \sqrt{2} = \sqrt{3 \cdot 2} = \sqrt{6} \)
\( 3\sqrt{2} \cdot \sqrt{2} + \sqrt{6} = 3 \cdot 2 + \sqrt{6} = 6 + \sqrt{6} \)
\( 0,5\sqrt{24} = \frac{1}{2}\sqrt{4 \cdot 6} = \frac{1}{2} \cdot 2\sqrt{6} = \sqrt{6} \)
\( (6 + \sqrt{6}) - \sqrt{6} \)
\( 6 + \sqrt{6} - \sqrt{6} = 6 \)
Ответ: 6