Ответ:

  1. \(7\frac{12}{13}-(4+2\frac{3}{5})=7\frac{12}{13}-6\frac{3}{5}=\frac{103}{13}-\frac{33}{5}=\frac{515-429}{65}=\frac{86}{65}=1\frac{21}{65}\).

  2. \(10\frac{14}{25}-(8+\frac{1}{5})=10\frac{14}{25}-8\frac{1}{5}=\frac{264}{25}-\frac{205}{25}=\frac{59}{25}=2\frac{9}{25}\).

  3. \(7-(4\frac{2}{17}-2\frac{3}{34})=7-(4\frac{4}{34}-2\frac{3}{34})=7-2\frac{1}{34}=4\frac{33}{34}\).

Ответ: 1 21/65; 2 9/25; 4 33/34.