Решение:
- \(3(8a-4)+6a = 24a - 12 + 6a = 30a - 12\)
- \(2(y-1)-2y+12 = 2y - 2 - 2y + 12 = 10\)
- \(7x-2(3x-1) = 7x - 6x + 2 = x + 2\)
- \(3-17a-11(2a-3) = 3 - 17a - 22a + 33 = 36 - 39a\)
- \(11c+5(8-c) = 11c + 40 - 5c = 6c + 40\)
- \(16+3(2-3y)+8y = 16 + 6 - 9y + 8y = 22 - y\)
- \(-4(3a+2)+8 = -12a - 8 + 8 = -12a\)
- \(15-5(1-a)-6a = 15 - 5 + 5a - 6a = 10 - a\)
Ответ: 1) \(30a-12\), 2) \(10\), 3) \(x+2\), 4) \(36-39a\), 5) \(6c+40\), 6) \(22-y\), 7) \(-12a\), 8) \(10-a\).