Mathematical problem
The line tx + 2y - 9 = 0 is parallel to the line 24x - 4y + 3 = 0. Determine the numerical value of t.
The direction coefficient of the second line k =
Parameter t =
Solution:
- The general form of a linear equation is Ax + By + C = 0.
- For the first line, tx + 2y - 9 = 0, the coefficients are A1 = t, B1 = 2, C1 = -9.
- For the second line, 24x - 4y + 3 = 0, the coefficients are A2 = 24, B2 = -4, C2 = 3.
- Two lines are parallel if their slopes are equal. The slope (m) of a line in the form Ax + By + C = 0 is given by m = -A/B.
- Slope of the first line (m1) = -t/2.
- Slope of the second line (m2) = -24/(-4) = 6.
- Since the lines are parallel, m1 = m2.
- Therefore, -t/2 = 6.
- Multiplying both sides by 2, we get -t = 12.
- Multiplying by -1, we get t = -12.
- The direction coefficient k is the slope of the second line, which is m2 = 6.
Final Answer:
Parameter t = -12
The direction coefficient k = 6