Ответ:
Использованы формулы: \((a\pm b)^2=a^2\pm2ab+b^2\), \(a^2-b^2=(a-b)(a+b)\), \(a^3\pm b^3=(a\pm b)(a^2\mp ab+b^2)\).
| № | 6.1 | 6.2 | 6.3 | 6.4 |
|---|---|---|---|---|
| 1 | \(x^2-2x+1\) | \((3-x)(3+x)\) | \((c-4)(c+4)\) | \(a^2-1\) |
| 2 | \(x^2+8x+16\) | \(x^2+25\) | \(4x^2-4x+1\) | \(b^2+8b+16\) |
| 3 | \((x-5)(x+5)\) | \((4x-1)(4x+1)\) | \(x^2+6xy+9y^2\) | \(25c^2-30c+9\) |
| 4 | \(4a^2-1\) | \(9x^2+12x+4\) | \((4x-5)(4x+5)\) | \(x^2+5\) |
| 5 | \((a+2)^2\) | \(49x^2-14x+1\) | \((x+2)^2\) | \((x-y^2)(x+y^2)\) |
| 6 | \(9a^2-6a+1\) | \((7x-3)(7x+3)\) | \(0.04-x^2\) | \(4x^2-20x+25\) |
| 7 | \((4-\frac{x}{2})(4+\frac{x}{2})\) | \((5x+2)^2\) | \(x^2-x+0.25\) | \((3y+2)^2\) |
| 8 | \((5x-1)^2\) | \((4y-3)^2\) | \(x^2+9\) | \((0.2x+0.1)^2\) |
| 9 | \((x-0.4)(x+0.4)\) | \(0.04y^2-1\) | \(121-x^2\) | \((x-\frac{3}{x})(x+\frac{3}{x})\) |
| 10 | \(x^2+2x+4\) | \((x-1)^2\) | \((x-4)^2\) | \(\frac{9}{25}-x^2\) |
| 11 | \((7-x^4)(7+x^4)\) | \((x+3)^2\) | \((y-x^4)(y+x^4)\) | \(9x^2+y^2\) |
| 12 | \((x-8)(x+8)\) | \(64-x^2\) | \(x^8+y^2\) | \(0.25-0.16x^2\) |
| 13 | \(x^2+64\) | \((1-y^5)(1+y^5)\) | \((5x+1)^2\) | \(\frac{x^2}{16}-y^2\) |
| 14 | \((a+1)(a^2-a+1)\) | \(x^2+x+0.25\) | \(-(a+b)^2\) | \(-(x+1)^2\) |
| 15 | \(a^3-8\) | \(a^3-1\) | \((1-c)(1+c+c^2)\) | \((a-b)(a^2+ab+b^2)\) |
| 16 | \((1-2x)(1+2x+4x^2)\) | \(a^3+27\) | \((x+10)(x^2-10x+100)\) | \((2x+1)(4x^2-2x+1)\) |
| 17 | \(m^6+64\) | \((5-a)(a^2+5a+25)\) | \(a^3-64\) | \(27y^3-\frac{1}{27}\) |
| 18 | \((n+1)(n^2-n+1)\) | \((a+0.1)(a^2-0.1a+0.01)\) | \(a^3+216\) | \(8+\frac{x^3}{125}\) |
| 19 | \(x^3+9x^2+27x+27\) | \(x^3-6x^2+12x-8\) | \(x^3+12x^2+48x+64\) | \(\frac{x^3}{8}+\frac{3x^2}{4}+\frac{3x}{2}+1\) |
| 20 | \(x^3-3x^2+3x-1\) | \(x^3+3x^2+3x+1\) | \(8x^3-12x^2+6x-1\) | \(x^3-15x^2+75x-125\) |
Выражения \(x^2+25\), \(x^2+5\), \(x^2+9\), \(x^2+64\), \(x^8+y^2\), \(9x^2+y^2\), \(m^6+64\) и некоторые аналогичные суммы квадратов над действительными числами формулами сокращённого умножения не раскладываются.
