Сравните дроби: 7/12, 5/7; 2/5 и 3/7; 11/20 и 8/15; 3/8 и 1/6; 9/16 и 7/12.

Решение:

Сравнение дробей:

1. \(\frac{7}{12}\) и \(\frac{5}{7}\)
2. \(7 \cdot 7 = 49\), \(12 \cdot 5 = 60\)
3. \(49 < 60\), значит, \(\frac{7}{12} < \frac{5}{7}\)

1. \(\frac{2}{5}\) и \(\frac{3}{7}\)
2. \(2 \cdot 7 = 14\), \(5 \cdot 3 = 15\)
3. \(14 < 15\), значит, \(\frac{2}{5} < \frac{3}{7}\)

1. \(\frac{11}{20}\) и \(\frac{8}{15}\)
2. \(11 \cdot 15 = 165\), \(20 \cdot 8 = 160\)
3. \(165 > 160\), значит, \(\frac{11}{20} > \frac{8}{15}\)

1. \(\frac{3}{8}\) и \(\frac{1}{6}\)
2. \(3 \cdot 6 = 18\), \(8 \cdot 1 = 8\)
3. \(18 > 8\), значит, \(\frac{3}{8} > \frac{1}{6}\)

1. \(\frac{9}{16}\) и \(\frac{7}{12}\)
2. \(9 \cdot 12 = 108\), \(16 \cdot 7 = 112\)
3. \(108 < 112\), значит, \(\frac{9}{16} < \frac{7}{12}\)

Ответ:
\(\frac{7}{12} < \frac{5}{7}\);
\(\frac{2}{5} < \frac{3}{7}\);
\(\frac{11}{20} > \frac{8}{15}\);
\(\frac{3}{8} > \frac{1}{6}\);
\(\frac{9}{16} < \frac{7}{12}\)