Solve the following arithmetic problems: 120 * 6 = ? 240 / 4 = ? 480 / 30 = ? 150 * 2 = ? 160 * 4 = ? 500 / 5 = ? Fill in the missing digits in the addition and subtraction problems: 3?8 + 43? ----- 8?0 ?9 + 38? ----- ?45 ?14 + ?78 ----- 94 8? - 37 ---- 16

Arithmetic Problems:

• \[ 120 \times 6 = 720 \]
• \[ 240 : 4 = 60 \]
• \[ 480 : 30 = 16 \]
• \[ 150 \times 2 = 300 \]
• \[ 160 \times 4 = 640 \]
• \[ 500 : 5 = 100 \]

Filling in the Missing Digits:

Addition 1:

Explanation: To get 0 in the units place of the sum, we need to add 8 and 3, which gives 11. We write down 0 and carry over 1. In the tens place, 7 + 3 + 1 (carry-over) = 11. We write down 1 and carry over 1. In the hundreds place, 3 + 4 + 1 (carry-over) = 8. So the missing digits are 7 and 0.

Addition 2:

Explanation: To get 6 in the units place of the sum, we need to add 9 and 7, which gives 16. We write down 6 and carry over 1. In the tens place, 7 + 8 + 1 (carry-over) = 16. We write down 6 and carry over 1. In the hundreds place, 9 + 3 + 1 (carry-over) = 13. So the missing digits are 7 and 6.

Addition 3:

Explanation: To get 4 in the units place of the sum, we need to add 4 and 8, which gives 12. We write down 2 and carry over 1. In the tens place, 1 + 7 + 1 (carry-over) = 9. In the hundreds place, 1 + 8 = 9. So the missing digits are 1 and 8, and the unit digit is 2. Note that the question states 94, which means the correct sum of the units digits should be 4. So 4+8 = 12. The unit digit is 2, and we carry over 1. For the tens digit, we have 1+7+1(carry over)=9. The missing digit in the first number is 1, and in the second number is 8. The answer should be 992 not 942. If we assume the result 94 is correct, then 1+7=8 so the missing digit is 1. and 4+8=12 so the missing digit is 2. So the missing digits are 1 and 8. The sum is 992.

Subtraction:

Explanation: To get 6 in the units place of the difference, we need to subtract 7 from a number. If we borrow 1 from the tens place, then 10 + units digit - 7 = 6. So the units digit must be 3. Thus, the top number's units digit is 3. Now, in the tens place, we have 7 - 1 (borrowed) - 3 = 3. This does not match the given result of 16. Let's re-examine. If the units digit of the difference is 6, and we subtract 7, we must have borrowed from the tens place. So, the tens digit of the top number is x. Then, x-1 (borrowed) - 3 = 1. This means x-4 = 1, so x = 5. Therefore, the top number should be 57. Let's check: 57 - 37 = 20. This is also incorrect. Let's assume the result 16 is correct. Then, the units digit is 6. If we subtract 7, we must have borrowed 1 from the tens digit. So, the units digit of the top number is U. Then U - 7 ends in 6. So U must be 3 (since 13-7=6). So the top number is in the form _3. Now for the tens digit. Let the tens digit of the top number be T. Then T - 1 (borrowed) - 3 = 1. This means T - 4 = 1, so T = 5. The top number is 53. 53 - 37 = 16. This is correct. So the missing digit is 7, and the tens digit of the top number is 5.