СЛОЖЕНИЕ С ПЕРЕХОДОМ ЧЕРЕЗ ДЕСЯТОК (ВИДА + 6, 7, 8, 9)

Решение:

В этом задании нужно решить примеры на сложение с переходом через десяток. Для каждого примера мы разложим одно из слагаемых так, чтобы сначала получить 10, а затем прибавить оставшуюся часть.

• 6 + 6 = 6 + (4 + 2) = (6 + 4) + 2 = 10 + 2 = 12
• 7 + 6 = 7 + (3 + 3) = (7 + 3) + 3 = 10 + 3 = 13
• 8 + 6 = 8 + (2 + 4) = (8 + 2) + 4 = 10 + 4 = 14
• 9 + 6 = 9 + (1 + 5) = (9 + 1) + 5 = 10 + 5 = 15
• 8 + 6 = 8 + (2 + 4) = (8 + 2) + 4 = 10 + 4 = 14
• 5 + 6 = 5 + (5 + 1) = (5 + 5) + 1 = 10 + 1 = 11
• 7 + 6 = 7 + (3 + 3) = (7 + 3) + 3 = 10 + 3 = 13
• 7 + 6 = 7 + (3 + 3) = (7 + 3) + 3 = 10 + 3 = 13
• 6 + 6 = 6 + (4 + 2) = (6 + 4) + 2 = 10 + 2 = 12
• 5 + 6 = 5 + (5 + 1) = (5 + 5) + 1 = 10 + 1 = 11
• 4 + 7 = 4 + (6 + 1) = (4 + 6) + 1 = 10 + 1 = 11
• 9 + 7 = 9 + (1 + 6) = (9 + 1) + 6 = 10 + 6 = 16
• 8 + 7 = 8 + (2 + 5) = (8 + 2) + 5 = 10 + 5 = 15
• 6 + 7 = 6 + (4 + 3) = (6 + 4) + 3 = 10 + 3 = 13
• 5 + 7 = 5 + (5 + 2) = (5 + 5) + 2 = 10 + 2 = 12
• 7 + 7 = 7 + (3 + 4) = (7 + 3) + 4 = 10 + 4 = 14
• 5 + 7 = 5 + (5 + 2) = (5 + 5) + 2 = 10 + 2 = 12
• 6 + 7 = 6 + (4 + 3) = (6 + 4) + 3 = 10 + 3 = 13
• 4 + 8 = 4 + (6 + 2) = (4 + 6) + 2 = 10 + 2 = 12
• 3 + 8 = 3 + (7 + 1) = (3 + 7) + 1 = 10 + 1 = 11
• 8 + 8 = 8 + (2 + 6) = (8 + 2) + 6 = 10 + 6 = 16
• 3 + 8 = 3 + (7 + 1) = (3 + 7) + 1 = 10 + 1 = 11
• 6 + 8 = 6 + (4 + 4) = (6 + 4) + 4 = 10 + 4 = 14
• 5 + 8 = 5 + (5 + 3) = (5 + 5) + 3 = 10 + 3 = 13
• 2 + 9 = 2 + (8 + 1) = (2 + 8) + 1 = 10 + 1 = 11
• 5 + 9 = 5 + (5 + 4) = (5 + 5) + 4 = 10 + 4 = 14
• 3 + 9 = 3 + (7 + 2) = (3 + 7) + 2 = 10 + 2 = 12
• 6 + 9 = 6 + (4 + 5) = (6 + 4) + 5 = 10 + 5 = 15
• 7 + 9 = 7 + (3 + 6) = (7 + 3) + 6 = 10 + 6 = 16
• 4 + 9 = 4 + (6 + 3) = (4 + 6) + 3 = 10 + 3 = 13

Ответ: 12, 13, 14, 15, 14, 11, 13, 13, 12, 11, 11, 16, 15, 13, 12, 14, 12, 13, 12, 11, 16, 11, 14, 13, 11, 14, 12, 15, 16, 13.