Вопрос:
Сложение и вычитание дробей с разными знаменателями. Случай 1. Вычислите: 1) 3/7 + 16/28; 2) 1/6 + 5/18; 3) 5/7 + 3/14; 4) 7/15 + 3/5; 5) 7/15 + 1/3; 6) 2/30 + 3/5; 7) 2/7 + 4/21; 8) 3/5 + 11/20; 9) 1/5 + 8/15; 10) 12/27 + 2/3; 11) 15/81 + 2/9; 12) 7/49 + 1/7; 13) 3/2 + 10/16; 14) 10/64 + 1/8; 15) 7/3 + 14/27; 16) 8/10 + 1/100; 17) 11/100 + 1/5; 18) 112/4 + 10/100; 19) 1/70 + 4/210; 20) 14/30 + 18/150; 21) 3/75 + 71/450; 22) 4/7 − 16/28; 23) 4/6 − 5/18; 24) 2/7 − 3/14; 25) 7/15 − 1/5; 26) 10/15 − 2/3; 27) 22/9 − 7/3; 28) 4/7 − 4/21; 29) 3/5 − 11/20; 30) 3/5 − 8/15; 31) 21/27 − 2/3; 32) 63/81 − 6/9; 33) 48/49 − 4/7; 34) 10/64 − 1/8; 35) 7/3 − 14/27; 36) 8/10 − 1/100; 37) 40/100 − 1/5; 38) 112/4 − 10/100; 39) 10/70 − 4/210; 40) 13/900 − 7/450.
Ответ:
- \(\frac{3}{7}+\frac{16}{28}=\frac{3}{7}+\frac{4}{7}=1\)
- \(\frac{1}{6}+\frac{5}{18}=\frac{3}{18}+\frac{5}{18}=\frac{4}{9}\)
- \(\frac{5}{7}+\frac{3}{14}=\frac{10}{14}+\frac{3}{14}=\frac{13}{14}\)
- \(\frac{7}{15}+\frac{3}{5}=\frac{7}{15}+\frac{9}{15}=\frac{16}{15}\)
- \(\frac{7}{15}+\frac{1}{3}=\frac{7}{15}+\frac{5}{15}=\frac{4}{5}\)
- \(\frac{2}{30}+\frac{3}{5}=\frac{1}{15}+\frac{9}{15}=\frac{2}{3}\)
- \(\frac{2}{7}+\frac{4}{21}=\frac{6}{21}+\frac{4}{21}=\frac{10}{21}\)
- \(\frac{3}{5}+\frac{11}{20}=\frac{12}{20}+\frac{11}{20}=\frac{23}{20}\)
- \(\frac{1}{5}+\frac{8}{15}=\frac{3}{15}+\frac{8}{15}=\frac{11}{15}\)
- \(\frac{12}{27}+\frac{2}{3}=\frac{4}{9}+\frac{6}{9}=\frac{10}{9}\)
- \(\frac{15}{81}+\frac{2}{9}=\frac{5}{27}+\frac{6}{27}=\frac{11}{27}\)
- \(\frac{7}{49}+\frac{1}{7}=\frac{1}{7}+\frac{1}{7}=\frac{2}{7}\)
- \(\frac{3}{2}+\frac{10}{16}=\frac{3}{2}+\frac{5}{8}=\frac{17}{8}\)
- \(\frac{10}{64}+\frac{1}{8}=\frac{5}{32}+\frac{4}{32}=\frac{9}{32}\)
- \(\frac{7}{3}+\frac{14}{27}=\frac{63}{27}+\frac{14}{27}=\frac{77}{27}\)
- \(\frac{8}{10}+\frac{1}{100}=\frac{80}{100}+\frac{1}{100}=\frac{81}{100}\)
- \(\frac{11}{100}+\frac{1}{5}=\frac{11}{100}+\frac{20}{100}=\frac{31}{100}\)
- \(\frac{112}{4}+\frac{10}{100}=28+\frac{1}{10}=\frac{281}{10}\)
- \(\frac{1}{70}+\frac{4}{210}=\frac{3}{210}+\frac{4}{210}=\frac{1}{30}\)
- \(\frac{14}{30}+\frac{18}{150}=\frac{70}{150}+\frac{18}{150}=\frac{44}{75}\)
- \(\frac{3}{75}+\frac{71}{450}=\frac{18}{450}+\frac{71}{450}=\frac{89}{450}\)
- \(\frac{4}{7}-\frac{16}{28}=\frac{4}{7}-\frac{4}{7}=0\)
- \(\frac{4}{6}-\frac{5}{18}=\frac{12}{18}-\frac{5}{18}=\frac{7}{18}\)
- \(\frac{2}{7}-\frac{3}{14}=\frac{4}{14}-\frac{3}{14}=\frac{1}{14}\)
- \(\frac{7}{15}-\frac{1}{5}=\frac{7}{15}-\frac{3}{15}=\frac{4}{15}\)
- \(\frac{10}{15}-\frac{2}{3}=\frac{2}{3}-\frac{2}{3}=0\)
- \(\frac{22}{9}-\frac{7}{3}=\frac{22}{9}-\frac{21}{9}=\frac{1}{9}\)
- \(\frac{4}{7}-\frac{4}{21}=\frac{12}{21}-\frac{4}{21}=\frac{8}{21}\)
- \(\frac{3}{5}-\frac{11}{20}=\frac{12}{20}-\frac{11}{20}=\frac{1}{20}\)
- \(\frac{3}{5}-\frac{8}{15}=\frac{9}{15}-\frac{8}{15}=\frac{1}{15}\)
- \(\frac{21}{27}-\frac{2}{3}=\frac{7}{9}-\frac{6}{9}=\frac{1}{9}\)
- \(\frac{63}{81}-\frac{6}{9}=\frac{7}{9}-\frac{6}{9}=\frac{1}{9}\)
- \(\frac{48}{49}-\frac{4}{7}=\frac{48}{49}-\frac{28}{49}=\frac{20}{49}\)
- \(\frac{10}{64}-\frac{1}{8}=\frac{5}{32}-\frac{4}{32}=\frac{1}{32}\)
- \(\frac{7}{3}-\frac{14}{27}=\frac{63}{27}-\frac{14}{27}=\frac{49}{27}\)
- \(\frac{8}{10}-\frac{1}{100}=\frac{80}{100}-\frac{1}{100}=\frac{79}{100}\)
- \(\frac{40}{100}-\frac{1}{5}=\frac{2}{5}-\frac{1}{5}=\frac{1}{5}\)
- \(\frac{112}{4}-\frac{10}{100}=28-\frac{1}{10}=\frac{279}{10}\)
- \(\frac{10}{70}-\frac{4}{210}=\frac{30}{210}-\frac{4}{210}=\frac{13}{105}\)
- \(\frac{13}{900}-\frac{7}{450}=\frac{13}{900}-\frac{14}{900}=-\frac{1}{900}\)