Simplify the expression: -4y² (5y - 1) +3y (2y²-y)

First, distribute -4y² to the terms in the first parentheses:

\( -4y^2 \cdot 5y = -20y^{2+1} = -20y^3 \)

\( -4y^2 \cdot (-1) = 4y^2 \)

So, the first part is -20y³ + 4y².

Next, distribute 3y to the terms in the second parentheses:

\( 3y \cdot 2y^2 = 6y^{1+2} = 6y^3 \)

\( 3y \cdot (-y) = -3y^{1+1} = -3y^2 \)

So, the second part is 6y³ - 3y².

Now, combine the results:

\( (-20y^3 + 4y^2) + (6y^3 - 3y^2) = -20y^3 + 4y^2 + 6y^3 - 3y^2 \)

Combine like terms:

\( (-20y^3 + 6y^3) + (4y^2 - 3y^2) = -14y^3 + y^2 \)

Ответ: -14y³ + y².