\(x=11\frac{4}{9}-3\frac{5}{12}=\frac{103}{9}-\frac{41}{12}=\frac{412-123}{36}=\frac{289}{36}=8\frac{1}{36}\).
\(x= -2\frac{7}{19}\cdot1\frac{4}{15}=-\frac{45}{19}\cdot\frac{19}{15}=-3\).
\(x=-2\frac{2}{11}\cdot\left(-1\frac{5}{6}\right)=-\frac{24}{11}\cdot\left(-\frac{11}{6}\right)=4\).
Ответ: а) \(8\frac{1}{36}\); б) \(-3\); в) \(4\).