Решение:
- Уравнение а:
- 0,8x + 1,4 = 1,4x - 2,6
- 1,4 + 2,6 = 1,4x - 0,8x
- 4 = 0,6x
- x = \frac{4}{0,6}\)
- x = \frac{40}{6}\)
- x = \frac{20}{3}\)
- Уравнение б:
- \(2\frac{2}{5}x + 3\frac{2}{15} = 3\frac{1}{5}x + 2\frac{1}{3}\)
- \(\frac{12}{5}x + \frac{47}{15} = \frac{16}{5}x + \frac{7}{3}\)
- \(\frac{47}{15} - \frac{7}{3} = \frac{16}{5}x - \frac{12}{5}x\)
- \(\frac{47}{15} - \frac{35}{15} = \frac{4}{5}x\)
- \(\frac{12}{15} = \frac{4}{5}x\)
- \(\frac{4}{5} = \frac{4}{5}x\)
- x = 1
- Уравнение в:
- \(\frac{1}{4} - \frac{1}{3}x = 4\frac{1}{4} - 3x\)
- \(\frac{1}{4} - \frac{17}{4} = \frac{1}{3}x - 3x\)
- \(-\frac{16}{4} = \frac{1}{3}x - \frac{9}{3}x\)
- -4 = -\frac{8}{3}x\)
- x = -4 \times (-\frac{3}{8})\)
- x = \frac{12}{8}\)
- x = \frac{3}{2}\)
Ответ: а) x = \frac{20}{3}; б) x = 1; в) x = \frac{3}{2}