Решим уравнение:
$$7 - (x + 1\frac{3}{5})=2\frac{4}{5}$$
$$7 - (x + \frac{1 \cdot 5 + 3}{5}) = \frac{2 \cdot 5 + 4}{5}$$
$$7 - (x + \frac{8}{5}) = \frac{14}{5}$$
$$7 - x - \frac{8}{5} = \frac{14}{5}$$
$$-x = \frac{14}{5} - 7 + \frac{8}{5}$$
$$-x = \frac{14}{5} + \frac{8}{5} - 7$$
$$-x = \frac{14+8}{5} - 7$$
$$-x = \frac{22}{5} - 7$$
$$-x = \frac{22}{5} - \frac{7 \cdot 5}{5}$$
$$-x = \frac{22}{5} - \frac{35}{5}$$
$$-x = \frac{22-35}{5}$$
$$-x = \frac{-13}{5}$$
$$x = \frac{13}{5}$$
$$x = 2\frac{3}{5}$$
Ответ: $$x = 2\frac{3}{5}$$