Приведем дроби \(\frac{1}{4}\), \(\frac{5}{6}\), \(\frac{3}{8}\), \(\frac{7}{12}\) к знаменателю 24:
- \(\frac{1}{4} = \frac{1 \cdot 6}{4 \cdot 6} = \frac{6}{24}\)
- \(\frac{5}{6} = \frac{5 \cdot 4}{6 \cdot 4} = \frac{20}{24}\)
- \(\frac{3}{8} = \frac{3 \cdot 3}{8 \cdot 3} = \frac{9}{24}\)
- \(\frac{7}{12} = \frac{7 \cdot 2}{12 \cdot 2} = \frac{14}{24}\)
Ответ: \(\frac{6}{24}\), \(\frac{20}{24}\), \(\frac{9}{24}\), \(\frac{14}{24}\)