a) \(\frac{17}{6}\) = \(2\frac{5}{6}\)
б) \(\frac{83}{7}\) = \(11\frac{6}{7}\)
в) \(\frac{73}{5}\) = \(14\frac{3}{5}\)
г) \(\frac{59}{18}\) = \(3\frac{5}{18}\)
д) \(\frac{86}{15}\) = \(5\frac{11}{15}\)
а) \(3\frac{1}{6}\) = \(\frac{3 \cdot 6 + 1}{6}\) = \(\frac{19}{6}\)
б) \(15\frac{1}{3}\) = \(\frac{15 \cdot 3 + 1}{3}\) = \(\frac{46}{3}\)
в) \(4\frac{8}{9}\) = \(\frac{4 \cdot 9 + 8}{9}\) = \(\frac{44}{9}\)
г) \(4\frac{14}{17}\) = \(\frac{4 \cdot 17 + 14}{17}\) = \(\frac{82}{17}\)
д) \(2\frac{5}{18}\) = \(\frac{2 \cdot 18 + 5}{18}\) = \(\frac{41}{18}\)
а) \(1-\frac{9}{11}\) = \(\frac{11}{11} - \frac{9}{11}\) = \(\frac{2}{11}\)
б) \(5-\frac{13}{17}\) = \(\frac{5 \cdot 17}{17} - \frac{13}{17}\) = \(\frac{85}{17} - \frac{13}{17}\) = \(\frac{72}{17}\) = \(4\frac{4}{17}\)
в) \(12-5\frac{1}{13}\) = \(12 - \frac{5 \cdot 13 + 1}{13}\) = \(12 - \frac{66}{13}\) = \(\frac{12 \cdot 13}{13} - \frac{66}{13}\) = \(\frac{156}{13} - \frac{66}{13}\) = \(\frac{90}{13}\) = \(6\frac{12}{13}\)
г) \(9-8\frac{5}{12}\) = \(9 - \frac{8 \cdot 12 + 5}{12}\) = \(9 - \frac{101}{12}\) = \(\frac{9 \cdot 12}{12} - \frac{101}{12}\) = \(\frac{108}{12} - \frac{101}{12}\) = \(\frac{7}{12}\)
а) \(13\frac{11}{13}-11\frac{8}{13}\) = \((13 - 11) + (\frac{11}{13} - \frac{8}{13})\) = \(2 + \frac{3}{13}\) = \(2\frac{3}{13}\)
б) \(6\frac{11}{25}-1\frac{22}{25}\) = \((6 - 1) + (\frac{11}{25} - \frac{22}{25})\) = \(5 - \frac{11}{25}\) = \(\frac{5 \cdot 25}{25} - \frac{11}{25}\) = \(\frac{125}{25} - \frac{11}{25}\) = \(\frac{114}{25}\) = \(4\frac{14}{25}\)
в) \(13\frac{2}{5}-12\frac{4}{5}\) = \((13 - 12) + (\frac{2}{5} - \frac{4}{5})\) = \(1 - \frac{2}{5}\) = \(\frac{5}{5} - \frac{2}{5}\) = \(\frac{3}{5}\)
г) \(6\frac{25}{28}-5\frac{25}{28}\) = \((6 - 5) + (\frac{25}{28} - \frac{25}{28})\) = \(1 + 0\) = \(1\)
Ответ: См. выше
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