2. Представьте смешанное число в виде суммы, а затем в виде неправильной дроби: 1) $$3\frac{4}{11} =$$ 2) $$4\frac{5}{6} =$$ 3) $$3\frac{7}{18} =$$ 4) $$11\frac{2}{3} =$$ 5) $$5\frac{11}{12} =$$ 6) $$8\frac{3}{9} =$$

1) $$3\frac{4}{11} = 3 + \frac{4}{11} = \frac{3 \cdot 11 + 4}{11} = \frac{33+4}{11} = \frac{37}{11}$$ 2) $$4\frac{5}{6} = 4 + \frac{5}{6} = \frac{4 \cdot 6 + 5}{6} = \frac{24+5}{6} = \frac{29}{6}$$ 3) $$3\frac{7}{18} = 3 + \frac{7}{18} = \frac{3 \cdot 18 + 7}{18} = \frac{54+7}{18} = \frac{61}{18}$$ 4) $$11\frac{2}{3} = 11 + \frac{2}{3} = \frac{11 \cdot 3 + 2}{3} = \frac{33+2}{3} = \frac{35}{3}$$ 5) $$5\frac{11}{12} = 5 + \frac{11}{12} = \frac{5 \cdot 12 + 11}{12} = \frac{60+11}{12} = \frac{71}{12}$$ 6) $$8\frac{3}{9} = 8 + \frac{3}{9} = \frac{8 \cdot 9 + 3}{9} = \frac{72+3}{9} = \frac{75}{9} = \frac{25}{3}$$