а) $$\frac{4^{12} \cdot 25}{8^9} = \frac{(2^2)^{12} \cdot 5^2}{(2^3)^9} = \frac{2^{24} \cdot 5^2}{2^{27}} = \frac{5^2}{2^{27-24}} = \frac{25}{2^3} = \frac{25}{8} = 3\frac{1}{8} = 3.125$$
Ответ: $$3.125$$
б) Если $$x = -\frac{1}{3}$$, то $$3 + 6x^3 = 3 + 6 \cdot (-\frac{1}{3})^3 = 3 + 6 \cdot (-\frac{1}{27}) = 3 - \frac{6}{27} = 3 - \frac{2}{9} = 2\frac{7}{9}$$
Ответ: $$2\frac{7}{9}$$